stpcpy - copy a string returning a pointer to its end
#include <string.h>
char *stpcpy(char *dest, const char *src);
Feature Test Macro Requirements for glibc (see
feature_test_macros(7)):
stpcpy():
- Since glibc 2.10:
- _POSIX_C_SOURCE >= 200809L
- Before glibc 2.10:
- _GNU_SOURCE
The
stpcpy() function copies the string pointed to by
src
(including the terminating null byte ('\0')) to the array pointed to by
dest. The strings may not overlap, and the destination string
dest must be large enough to receive the copy.
stpcpy() returns a pointer to the
end of the string
dest
(that is, the address of the terminating null byte) rather than the beginning.
For an explanation of the terms used in this section, see
attributes(7).
Interface |
Attribute |
Value |
stpcpy () |
Thread safety |
MT-Safe |
This function was added to POSIX.1-2008. Before that, it was not part of the C
or POSIX.1 standards, nor customary on UNIX systems. It first appeared at
least as early as 1986, in the Lattice C AmigaDOS compiler, then in the GNU
fileutils and GNU textutils in 1989, and in the GNU C library by 1992. It is
also present on the BSDs.
This function may overrun the buffer
dest.
For example, this program uses
stpcpy() to concatenate
foo and
bar to produce
foobar, which it then prints.
#define _GNU_SOURCE
#include <string.h>
#include <stdio.h>
int
main(void)
{
char buffer[20];
char *to = buffer;
to = stpcpy(to, "foo");
to = stpcpy(to, "bar");
printf("%s\n", buffer);
}
bcopy(3),
memccpy(3),
memcpy(3),
memmove(3),
stpncpy(3),
strcpy(3),
string(3),
wcpcpy(3)